KHAEMENES ACADEMY · PHYSICS 12 · WEEK 25 · DAY 03

Interference, Beats & Standing Waves

Why do systems respond strongly at particular frequencies?

Explicit physics instruction

Superposition can produce constructive/destructive interference. Two nearby frequencies can create beats with a beat rate equal to the frequency difference.

Standing waves arise when reflections and superposition create persistent nodes and antinodes.

Boundary conditions determine the allowed standing-wave modes.

Core relation: v=fλ; resonance near natural frequency.

Worked example

Tones at 440 Hz and 444 Hz produce a 4 Hz beat pattern in the simple model.

Guided question

Two tones are 500 and 506 Hz. What beat frequency is predicted?

Independent work

  1. Solve three sound/resonance questions.
  2. Interpret one standing-wave or resonance graph.
  3. State one damping/boundary assumption.

Misconception check

Resonance does not mean energy is created; it means energy transfer from the driver is especially effective.

Formative check

What happens to response near a natural frequency?

Reveal response

Amplitude can increase because energy transfer from the driver becomes especially effective.

Mentor evidence conference

Ask Archaemenes to audit frequency/wavelength units, resonance evidence, and damping assumptions.

Teacher guidance

Foundation: Calculate with v=fλ and identify resonance.

Core: Interpret beats, standing waves, and resonance curves.

Extended: Analyze damping and engineering tradeoffs.