Problem 1
x=−y,z=−y, so kerT=span{(−1,1,−1)}.
Faculty use
Reward correct mathematics, explicit dimensions/hypotheses, interpretation, and verification. Equivalent valid reasoning should receive credit.
x=−y,z=−y, so kerT=span{(−1,1,−1)}.
The standard matrix has rank 2, so dim imT=2.
Definitions should identify the vector/matrix/space/transformation, dimensions or domain/codomain, and the hypotheses behind measuring collapsed inputs and attainable outputs. Use the formulas kerT={v:T(v)=0}; imT={T(v):v∈V}.
A strong error analysis identifies the first step that violates a definition, dimension, theorem hypothesis, or matrix-operation rule; then repairs that step and re-verifies the final result.
Application responses vary. Require defined variables, a compatible matrix/vector model connected to graphics, coordinate changes, differential operators, data pipelines, and reversible models, a complete computation, interpretation, and limitations.
Accept two independent checks appropriate to the task: reconstruction, residual, RREF comparison, determinant/rank test, orthogonality, substitution, eigenpair check Av=λv, factorization product, or a second method.
Six problems × 10 points: 5 mathematical accuracy, 2 structure/justification, 2 verification/interpretation, 1 notation and communication.