Grade 12 · Week 03 · Tuesday · Day 02

Velocity–Time Graphs

How does the slope of a velocity graph represent acceleration?

Objective: Interpret a velocity–time graph's signed slope and distinguish velocity changes from position changes.

45–60 minutes · Offline-capable · Public practice is not a supervised examination

Read and reason

The axes carry different units

A velocity–time graph plots signed velocity (m/s) vertically against elapsed time (s) horizontally. Slope is change of velocity divided by change of time, giving m/s². A horizontal line above zero is motion at constant positive velocity; a horizontal line below zero is constant negative velocity. A rising line means positive acceleration even if velocity remains negative for part of the interval.

Do not confuse the sign with speeding up

A line sloping downward from +4 m/s to 0 m/s indicates negative acceleration while speed decreases. Continue that same downward line from 0 to −4 m/s and the speed increases in the negative direction. At the zero crossing, the moving object briefly stops and reverses in a one-dimensional constant-acceleration model. The acceleration sign has not changed at the crossing.

Calculate an interval slope

If v changes from +3 m/s at t=1 s to −1 m/s at t=3 s, the slope is (−1−3)/(3−1)=−4/2=−2 m/s². A linear velocity–time graph corresponds to constant acceleration in our ideal model; a curved velocity–time graph would indicate changing acceleration. Averages over large intervals can miss important variation between points.

Model versus measurement

A motion sensor might report velocities at discrete times, not a perfect continuous line. To infer acceleration from real data, plot values with units, consider uncertainty and fit an appropriate trend. Graph displays depend on chosen axis scales, which should not alter the physical slope once the units are accounted for. The same object will have different velocity values in frames moving at fixed speed, but unchanged acceleration under a Galilean transformation.

Vocabulary

velocity–time graph
Graph with signed velocity (m/s) on the vertical axis and elapsed time (s) horizontally; slope is acceleration, signed area is displacement. Explain with an original example.
slope
Vertical change divided by horizontal change (rise/run) on a graph. Explain with an original example.
acceleration
Rate of change of vector velocity; in one dimension a=Δv/Δt (m/s²). Explain with an original example.
instantaneous
Evaluated at a particular moment rather than averaged over an interval. Explain with an original example.
average
A quantity describing an entire specified interval; e.g. Δv/Δt for average acceleration. Explain with an original example.

Worked example

At t=1 s, v=+3 m/s. At t=3 s, v=−1 m/s. Slope=(−1−3)/(3−1)=−2 m/s².

Check signs and units. Show each calculation rather than memorizing a number.

Your science journal

Calculate slopes for rising, flat and falling velocity–time segments; explain how a negative slope can correspond to either faster or slower motion.

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Daily Retrieval Practice · 4 Questions

Choose one answer to each question, check, read the feedback, and retry after correcting mistakes. Target 80% open-book mastery; public practice scores do not authenticate official midterms or finals.