Grade 12 · Week 09 · Tuesday

Gravity Weakens with Distance

Objective: Use Newton's universal gravitation and the inverse-square pattern accurately.

45–60 minutes · Complete offline lessons · Algebra and scientific reasoning

Reading: Develop the model

Two masses exert forces on one another

Newton's ideal gravitational interaction has magnitude F=Gm₁m₂/r², where r is separation between the masses' centers, G is the universal gravitational constant, and m₁ and m₂ are masses in kilograms. Both bodies experience equal and opposite forces, consistent with Newton's third law. Their resulting accelerations can differ because their masses differ.

Inverse square is not inverse linear

If separation doubles while both masses remain fixed, the gravitational force becomes one quarter as large. If separation triples it becomes one ninth as large. This is because r appears squared in the denominator. The Gravity Field Explorer can compare a starting radius with a larger radius and graph the force and field strength ratios.

Field strength and test mass

For a spherical central body outside its surface, gravitational field magnitude is g(r)=GM/r². A small test mass has force F=mg(r). The field strength is independent of the test mass even though the force it experiences is proportional to test mass. Earth is approximately spherical for this first-pass model; closer to real Earth, geography and shape make the field more complicated.

Center distance is not altitude

For a satellite at altitude h above Earth's surface, radial distance r=R_E+h, not r=h. Surface gravity follows GM/R_E²; at altitude, g(h)=GM/(R_E+h)². The Earth's radius itself is approximately 6371 km. Simply inserting 400 km as r in the inverse-square formula produces an extremely misleading result.

Five terms in context

universal gravitation
Inverse-square interaction between masses.
gravitational constant
Universal proportionality constant G≈6.67430×10⁻¹¹ N·m²/kg².
inverse-square law
Quantity scales as one divided by distance squared.
gravitational field
Acceleration per unit test mass due to the central body's gravity.
center-to-center distance
The separation r used in the gravitational equation.

Worked example

For unchanged masses, doubling r reduces F to F/4. For Earth, surface radius R≈6371 km and an altitude h=400 km give r≈6771 km. The field ratio g(h)/g(0)=(6371/6771)²≈0.885, so gravity is still substantial.

Show the radius measured from the central body's center, all units and rounding.

Science evidence notebook

Compute gravity/force ratios for radial-distance multiples 1, 2, 3, and 4. Explain why the graph slopes down steeply near Earth and why r must be measured from the center.

Browser-local notes only. Export JSON to preserve work across devices.

Daily · 4 Retrieval Questions

Public open-book formative practice with explanatory feedback and an 80% correction target, not an authenticated midterm or final.