Grade 12 · Week 09 · Wednesday

Circular Orbits: Speed and Period

Objective: Derive circular orbital speed and period by equating gravity with centripetal net force.

45–60 minutes · Complete offline lessons · Algebra and scientific reasoning

Reading: Develop the model

Use the correct inward force

An ideal satellite of mass m in a circular orbit of radius r around a central body of mass M requires centripetal net force mv²/r. Under the two-body approximation, gravity supplies it: GMm/r² = mv²/r. For nonzero satellite mass, cancel m and solve v=√(GM/r). Note that G and M appear together as gravitational parameter μ=GM.

How long for an orbit?

Orbital period is circumference divided by speed: T=2πr/v. Substituting circular speed gives T=2π√(r³/μ). Increasing radius lowers circular speed but lengthens the orbital period. Doubling orbital radius increases period by 2^(3/2), or about 2.83, in the ideal two-body model.

Compare an illustrative low Earth orbit

Using Earth's μ≈3.986004418×10¹⁴ m³/s², R≈6.371×10⁶ m, and altitude 400 km, r≈6.771×10⁶ m. Circular speed is around 7.67 km/s and period roughly 92.4 minutes. These are ideal-model estimates and not real-time tracking of any spacecraft.

Do not generalize outside the assumptions

Circular speed formula describes an ideal circular orbit around a dominant central mass. Elliptical speeds vary along the trajectory, actual bodies perturb one another, and atmospheric drag modifies low Earth orbits. The simulator does not model stationkeeping, ascent, maneuver planning, atmospheric entry or orbital debris.

Five terms in context

gravitational parameter
Product μ=GM describing a central body's gravitational influence.
circular orbital speed
Speed √(μ/r) for an ideal circular orbit.
orbital period
Time required for one revolution.
centripetal requirement
Inward net force of magnitude mv²/r for uniform circular motion.
two-body approximation
Simplification where one dominant gravitational interaction governs the motion.

Worked example

For r=6.771×10⁶ m around Earth, v=√(3.986004418×10¹⁴/6.771×10⁶)≈7673 m/s. Period T=2πr/v≈5544 s, or about 92.4 minutes.

Show the radius measured from the central body's center, all units and rounding.

Science evidence notebook

Estimate speed and period at 400 km and at 1000 km altitude using the Orbital Studio. Show formulas, units, and a claim about the relationship between orbit size and period.

Browser-local notes only. Export JSON to preserve work across devices.

Daily · 4 Retrieval Questions

Public open-book formative practice with explanatory feedback and an 80% correction target, not an authenticated midterm or final.