Grade 12 · Week 11 · Wednesday

Springs Store Elastic Energy

Learning objective: Calculate elastic potential energy for an ideal linear spring and distinguish force from stored energy.

45–60 minutes · Safe offline simulations · No physical apparatus required

Scientific reading and explanation

Elastic energy depends on deformation

For a spring behaving according to Hooke's law, F_s=−kx where x is displacement from its unstretched equilibrium and k is stiffness in N/m. The minus sign denotes restoring direction. The stored spring energy is U_s=½kx², nonnegative for either compression or extension. Doubling the deformation quadruples stored energy at fixed k.

Units matter twice

If k=200 N/m and spring compression is 0.20 m, stored U_s=½×200×(0.20)²=4 J. Entering 20 instead of 0.20 would mistakenly treat centimeters as meters and inflate the result by a factor of 10,000. Our sliders display centimeters but calculations convert them to meters before applying x².

A simplified release is not a full oscillator

The Spring Energy Lab models a compressed spring moving from initial deformation x_0 toward a smaller deformation x. Initially the spring carries U_0=½kx_0². The released amount ΔU=½k(x_0²−x²) becomes kinetic energy plus an explicitly selected nonmechanical transfer fraction. The model does not calculate signed velocity, contact details or complete back-and-forth oscillation.

Keep a coherent system account

For the ideal spring–object system, U_s+K is constant without energy transfers out of mechanical forms. In a more inclusive energy ledger, add thermal or other energy so the total stays constant even when mechanical energy decreases. If the moving body begins with its own kinetic energy, that initial kinetic energy must also be included; this lab assumes release from rest.

Vocabulary

Hooke's law
Restoring spring force F=−kx within the spring's linear range.
spring constant
Stiffness k, measured in N/m.
elastic potential energy
Stored energy U_s=½kx².
equilibrium length
Spring length with x=0 in the ideal model.
deformation
Compression or extension from equilibrium, measured in meters.

Worked example

A spring k=200 N/m compressed x_0=0.20 m stores 4 J. At compression x=0.10 m it retains 1 J and releases 3 J. With no loss and m=1.5 kg, kinetic energy is 3 J and speed magnitude=2 m/s.

Show system boundaries, units and a complete conservation ledger.

Student science journal

Compare k=100 and 200 N/m at equal compression, then compare x_0=10 and 20 cm at equal k. Show how the energy changes and identify squared deformation.

Browser-local journal. Export JSON for a portable copy.

Daily · 4 Practice Questions

Open-book formative assessment with explanations and an 80% correction target. These public exercises do not replace supervised midterms or finals.